Django添加feeds功能的示例

from django.contrib.syndication.views import Feed
from blog.models import Article
from django.conf import settings
from django.utils.feedgenerator import Rss201rev2Feed
from DjangoBlog.common_markdown import common_markdown
from django.contrib.auth import get_user_model
from django.contrib.auth.models import User
from django.contrib.sites.models import Site


class DjangoBlogFeed(Feed):
  feed_type = Rss201rev2Feed

  de ion = settings.SITE_DE ION
  feed_url = 'https://www.fkomm.cn/feed'
    = "%s %s " % (settings.SITE_NAME, settings.SITE_DE ION)
    = "https://www.fkomm.cn"

  def author_name(self):
    return get_user_model(). s.first().nickname

  def author_ (self):
    return get_user_model(). s.first().get_absolute_url()

  def items(self):
    return Article. s.order_by('-pk')[:5]

  def item_ (self, item):
    return item. 

  def item_de ion(self, item):
    return common_markdown.get_markdown(item.body)

  def feed_copyright(self):
    # print(Site. s.get_current().name)
    return "Copyright© 2018 " + settings.SITE_NAME

  def item_ (self, item):
    return item.get_absolute_url()

  def item_guid(self, item):
    return

from DjangoBlog.feeds import DjangoBlogFeed


urlpatterns = [
  ......
  url(r'^feed/$',DjangoBlogFeed()),
]