python判断数字是否是超级素数幂

import math


def get_prime(number):
  '''
  寻找小于number的所有的质数，时间复杂度o(n^2)
  '''
  if number <= 1:
    print 'Wrong given number.'
    return
  prime = []
  for i in xrange(2, number+1):
    j = 2
    while j < i:
      if i % j == 0:
        break
      j += 1
    if j == i:
      prime.append(i)
  return prime

def super_prime_power(number):
  scope = int(math.ceil(math.sqrt(number))) # 开根号除掉一部分不需要的数
  prime_number = get_prime(scope)
  be_tested = []
  for i in prime_number: # 先将无法被整数的排除掉
    if number % i == 0:
      be_tested.append(i)
  for p in be_tested:
    q = 2
    while p ** q <= number:
      if p ** q == number:
        return (p, q)
      q += 1
  return False

print super_prime_power(999)