1、先按照初学者思维代码应该是这样的
1 #coding:utf-8 2 import os 3 text = os.popen("adb shell command cat /proc/cpuinfo",'r').read().split("\\n") 4 i = 0 5 for j in text: 6 if "processor\\t:" in j: 7 i += 1 8 if i == 1: 9 print ("单核") 10 elif i == 2: 11 print ("2核") 12 elif i == 3: 13 print ("3核") 14 elif i == 4: 15 print ("4核") 16 elif i == 5: 17 print ("5核") 18 elif i == 6: 19 print ("6核") 20 elif i == 7: 21 print ("7核") 22 elif i == 8: 23 print ("8核")
上面的代码也没啥毛病,也能得出正确的结果,但代码有20多行,实在是影响代码的执行效率了
2、接下来看这个
1 #coding:utf-8 2 import os 3 i = 0 4 cores = ["单核","2核","3核","4核","5核","6核","7核","8核"] 5 text = os.popen("adb shell command cat /proc/cpuinfo",'r').read().split("\\n") 6 lst = [i+1 for j in text if "Processor\\t:" in j] 7 cpu_cores = cores[len(lst)-1] 8 print (cpu_cores)
得出的结果跟上面的一样,那这样看看哪个的执行效率更好些
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