python 使用值来排序一个字典的方法

In [8]: a={\'x\':11,\'y\':22,\'c\':4}
In [9]: import operator
In [10]: sorted(a.items(),key=operator.itemgetter(1))
Out[10]: [(\'c\', 4), (\'x\', 11), (\'y\', 22)]
In [11]: a={\'x\':11,\'y\':22,\'c\':4}
In [12]: sorted(a.items(),key=lambda x:x[1])
Out[12]: [(\'c\', 4), (\'x\', 11), (\'y\', 22)]

# sorted的结果是一个list
  dic1SortList = sorted( dic1.items(),key = lambda x:x[1],reverse = True)

import operator
sorted_x = sorted(d.items(),key = operator.itemgetter(1))

x = [{\'name\':\'Homer\', \'age\':39}, {\'name\':\'Bart\', \'age\':10}] 
sorted_x = sorted(x, key=operator.itemgetter(\'name\')) 
print sorted_x 
#[{\'age\': 10, \'name\': \'Bart\'}, {\'age\': 39, \'name\': \'Homer\'}] 
sorted_x = sorted(x, key=operator.itemgetter(\'name\'), reverse=True) 
print sorted_x 
#[{\'age\': 39, \'name\': \'Homer\'}, {\'age\': 10, \'name\': \'Bart\'}] 
sorted_x = sorted(x, key=lambda x : x[\'name\']) 
print sorted_x 
#[{\'age\': 10, \'name\': \'Bart\'}, {\'age\': 39, \'name\': \'Homer\'}] 
sorted_x = sorted(x, key=lambda x : x[\'name\'], reverse=True) 
print sorted_x 
#[{\'age\': 39, \'name\': \'Homer\'}, {\'age\': 10, \'name\': \'Bart\'}]