本文实例讲述了Python推导式。分享给大家供大家参考,具体如下:

1. 列表推导式

>>> li = [1,2,3,4,5,6]
# 求元素的平方
>>> li_a = [x**2 for x in li ]
>>> li_a
[1, 4, 9, 16, 25, 36]
# 提取偶数值
>>> li_b = [x for x in li if x%2==0]
>>> li_b
[2, 4, 6]
# 将多维数组转换成一维数组
>>> li_c = [[1,2], [3], [], [4,5,6]]
>>> li_d = [j for i in li_c for j in i ]
>>> li_d
[1, 2, 3, 4, 5, 6]
# 使用map
>>> li_1 = [\'a\', \'b\', \'c\', \'d\']
>>> li_2 = [10, 20, 30, 40]
>>> li_e = list(map(lambda x, y:{x:y}, li_1, li_2))
>>> li_e
[{\'a\': 10}, {\'b\': 20}, {\'c\': 30}, {\'d\': 40}]

2. 字典推导式

# 解析列表
>>> li = [\'a\', \'b\', \'c\', \'d\', \'e\']
>>> li_1 = {k:v for k, v in enumerate(li)}
>>> li_1
{0: \'a\', 1: \'b\', 2: \'c\', 3: \'d\', 4: \'e\'}
# 解析字典
>>> dict_a = {\'a\':10, \'b\':20, \'c\':30}
>>> dict_b = {v:k for k, v in dict_a.items()}
>>> dict_b
{10: \'a\', 20: \'b\', 30: \'c\'}

3. 集合推导式

>>> set1 = {x for x in range(10)}
>>> set1
set([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])

PS:上述代码在Python2.7与Python3.6环境下测试

更多关于Python相关内容可查看本站专题:《Python列表(list)操作技巧总结》、《Python字符串操作技巧汇总》、《Python数据结构与算法教程》、《Python函数使用技巧总结》、《Python入门与进阶经典教程》及《Python文件与目录操作技巧汇总

希望本文所述对大家Python程序设计有所帮助。

收藏 打印