DELETE consum_record FROM consum_record, ( SELECT min(id) id, user_id, monetary, consume_time FROM consum_record GROUP BY user_id, monetary, consume_time HAVING count(*) > 1 ) t2 WHERE consum_record.user_id = t2.user_id and consum_record.monetary = t2.monetary and consum_record.consume_time = t2.consume_time AND consum_record.id > t2.id;
上面这条sql语句,仔细看一下,揣摩出思路也不难,大概也分为3步来理解:
(SELECT min(id) id, user_id, monetary, consume_time FROM consum_record GROUP BY user_id, monetary, consume_time HAVING count(*) > 1 ) t2 查询出重复记录形成一个集合(临时表t2),集合里是每种重复记录的最小ID
consum_record.user_id = t2.user_id and consum_record.monetary = t2.monetary and consum_record.consume_time = t2.consume_time 关联 判断重复基准的字段
根据条件,删除原表中id大于t2中id的记录
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