本题要求实现一个字符串查找的简单函数。

函数接口定义:
char *search( char *s, char *t );
函数search在字符串s中查找子串t,返回子串t在s中的首地址。若未找到,则返回NULL。

裁判测试程序样例:
#include <stdio.h>
#define MAXS 30

char *search(char *s, char t);
void ReadString( char s[] ); /
裁判提供,细节不表 */

int main()
{
char s[MAXS], t[MAXS], *pos;

ReadString(s);
ReadString(t);
pos = search(s, t);
if ( pos != NULL )
    printf(\"%d\\n\", pos - s);
else
    printf(\"-1\\n\");

return 0;

}

/* 你的代码将被嵌在这里 */
输入样例1:
The C Programming Language
ram
输出样例1:
10
输入样例2:
The C Programming Language
bored
输出样例2:
-1

#include <stdio.h>
#define MAXS 30

char *search(char *s, char *t);
void ReadString( char s[] )/* 裁判提供,细节不表 */
{
    gets(s);
}

int main()
{
    char s[MAXS], t[MAXS], *pos;

    ReadString(s);
    ReadString(t);
    pos = search(s, t);
    if ( pos != NULL )
        printf(\"%d\\n\", pos - s);
    else
        printf(\"-1\\n\");

    return 0;
}

char *search( char *s, char *t )
{
    int len1 = strlen(s);
    int len2 = strlen(t);
    int i = 0, j = 0;
    while (i < len1 && j < len2)
    {
        if (s[i] == t[j]) {i++; j++;}
        else {i = i - j + 2; j = 1;}
    }
    if(j >= len2) return &s[i - j];
    return NULL;
}

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