使用Python解一元二次方程！

一元二次方程：ax² + bx + c = 0

求根公式：x = （-b+√(b²-4ac)）/2a 

判别式：b²-4ac

def my_math(a, b , c):

        if not isinstance(a,(int, float)) and not isinstance(b, (int, float)) and not isinstance(c, (int, float)) :
            raise TypeError(\"输入的参数类型有误\" + a)
        # elif not isinstance(b, (int, float)):
        #     raise TypeError(\"输入的参数类型有误\" + b)
        # elif not isinstance(c, (int, float)):
        #     raise TypeError(\"输入的参数类型有误\" + c)
        else:
            dist = pow(b,2) - (4 * a * c)
            print(dist)
            if dist == 0:
                result = -b / (2 * a)
                print(\"只有一个相同的实数：\", result)
            if dist < 0:
                print(\"没有实数\")
            if dist > 0:
                result1 = (-b + math.sqrt(dist)) /2 * a
                result2 = (-b - math.sqrt(dist)) / 2 * a
                print(result1)
                print(result2)


my_math(-6,6,6)