jquery ajax跨域的完美解决方法(jsonp方式)

1 $.ajax({

 2                     url: path+"/login/login?msg_ 64="+msg_ 64, 3                     async: false, 4 //                    data:{ 5 //                        "formContent":str, 6 //                        "formName":formName, 7 //                        "leixing":leixing 8 //                    }, 9                     dataType:"jsonp",10                     processData: false,     11                     type:"get",12                     success:function(data){13                         data=data[0];14                         alert(data);15                         if(data.status=="0"){16                             $("#usererror").html(data.msg);17                         }else if(data.status=="1"){18                             $("#pwderror").html(data.msg);19                             }20                         else if(data.status=="2"){21                             alert("水电费:"+data.data);22                             addCookie("token",data.data,1);//将令牌存入cookie中23                             window.location.href="edit.html";24                             }25                     }26                 });

 1 @ResponseBody // 将方法的返回结果自动转换为json格式字符串，注意需要导json的包 2     @RequestMapping(value = "/login", method = RequestMethod.GET) 3     public String login(HttpServletRequest request,String msg_ 64) { 4          5          6         String callback=request.getParameter("callback"); 7         //System.out.println(callback); 8                                                                 // 信息 9 //        String msg_context_ 64 = msg_ 64.split(" ")[1];10         String msg = NoteUtil. 64Decode(msg_ 64);// 解密，解密后：username:password11         String name = msg.split(":")[0];12         String pwd = msg.split(":")[1];13         NoteResult result = service.checkUser(name, pwd);14         System.out.println("result  "+result.toString());15         JSONArray json=JSONArray.from (result);16         System.out.println("  "+callback+"("+json+")");17         return callback+"("+json.toString()+")";18     }19