7-19 计算天数 （15 分）
本题要求编写程序计算某年某月某日是该年中的第几天。
输入格式:
输入在一行中按照格式“yyyy/mm/dd”（即“年/月/日”）给出日期。注意：闰年的判别...
7-19 计算天数 （15 分）
本题要求编写程序计算某年某月某日是该年中的第几天。
输入格式:
输入在一行中按照格式“yyyy/mm/dd”（即“年/月/日”）给出日期。注意：闰年的判别条件是该年年份能被4整除但不能被100整除、或者能被400整除。闰年的2月有29天。
输出格式:
在一行输出日期是该年中的第几天。
输入样例1:
2009/03/02
输出样例1:
61
输入样例2:
2000/03/02
输出样例2:
62
#include <stdio.h>
int main(){
int year,month,day;
scanf(\"%d/%d/%d\",&year,&month,&day);
if(year%400==0||(year%4==0&&year%100!=0))
{
switch(month){
case 1:
printf(\"%d\",day);
break;
case 2:
day=31+day;
printf(\"%d\",day);
break;
case 3:
day=31+29+day;
printf(\"%d\",day);
break;
case 4:
day=31+29+31+day;
printf(\"%d\",day);
break;
case 5:
day=31+29+31+30+day;
printf(\"%d\",day);
break;
case 6:
day=31+29+31+30+31+day;
printf(\"%d\",day);
break;
case 7:
day=31+29+31+30+31+30+day;
printf(\"%d\",day);
break;
case 8:
day=31+29+31+30+31+30+31+day;
printf(\"%d\",day);
break;
case 9:
day=31+29+31+30+31+30+31+31+day;
printf(\"%d\",day);
break;
case 10:
day=31+29+31+30+31+30+31+31+30+day;
printf(\"%d\",day);
break;
case 11:
day=31+29+31+30+31+30+31+31+30+31+day;
printf(\"%d\",day);
break;
case 12:
day=31+29+31+30+31+30+31+31+30+31+30+day;
printf(\"%d\",day);
break;
}
}
else{
switch(month){
case 1:
printf(\"%d\",day);
break;
case 2:
day=31+day;
printf(\"%d\",day);
break;
case 3:
day=31+28+day;
printf(\"%d\",day);
break;
case 4:
day=31+28+31+day;
printf(\"%d\",day);
break;
case 5:
day=31+28+31+30+day;
printf(\"%d\",day);
break;
case 6:
day=31+28+31+30+31+day;
printf(\"%d\",day);
break;
case 7:
day=31+28+31+30+31+30+day;
printf(\"%d\",day);
break;
case 8:
day=31+28+31+30+31+30+31+day;
printf(\"%d\",day);
break;
case 9:
day=31+28+31+30+31+30+31+31+day;
printf(\"%d\",day);
break;
case 10:
day=31+28+31+30+31+30+31+31+30+day;
printf(\"%d\",day);
break;
case 11:
day=31+28+31+30+31+30+31+31+30+31+day;
printf(\"%d\",day);
break;
case 12:
day=31+28+31+30+31+30+31+31+30+31+30+day;
printf(\"%d\",day);
break;
}
}
return 0;
}
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