leetcode判断一个链表是否为回文链表

# Definition for singly- ed list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def reverst(self,head):
        a=head
        b=head.next
        head.next = None;
        while b:
            c = b.next
            b.next = a
            a = b
            b=c
        head = a
        return head
        
    def isPalindrome(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        if not head or not head.next:
            return True
    
        fast = slow = head
        while fast.next and fast.next.next:
            slow = slow.next
            fast = fast.next.next
        slow = slow.next
        slow = self.reverst(slow)
        while slow:
            if head.val != slow.val:
                return False
            slow = slow.next
            head = head.next
        return True