Python 请求头headers的设置，模拟浏览器

从列表中随机抽取一个浏览器头作为函数的返回值。

def get_header():
    user_agent_list = [
        \'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95\',
        \'Safari/537.36 OPR/26.0.1656.60\',
        \'Opera/8.0 (Windows NT 5.1; U; en)\',
        \'Mozilla/5.0 (Windows NT 5.1; U; en; rv:1.8.1) Gecko/20061208 Firefox/2.0.0 Opera 9.50\',
        \'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:34.0) Gecko/20100101 Firefox/34.0\',
        \'Mozilla/5.0 (X11; U; Linux x86_64; zh-CN; rv:1.9.2.10) Gecko/20100922 Ubuntu/10.10 \'
        \'(maverick) Firefox/3.6.10\',
        \'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) \'
        \'Chrome/39.0.2171.71 Safari/537.36\',
        \'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.11 \'
        \'(KHTML, like Gecko) Chrome/23.0.1271.64 Safari/537.11\',
    ]
    UserAgent = random.choice(user_agent_list)
    header = {\'User-Agent\': UserAgent}
    return header